package leetcode;

/*
344. 反转字符串
编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。
不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。
示例 1：
输入：["h","e","l","l","o"]
输出：["o","l","l","e","h"]
示例 2：
输入：["H","a","n","n","a","h"]
输出：["h","a","n","n","a","H"]
*/

public class problems_344 {
    public static void main(String[] args) {
        new Solution().reverseString(new char[]{'h','e','l','l','o'});
        System.out.println();
    }

    static class Solution {
        public void reverseString(char[] s) {
            int left = 0;
            int right = s.length - 1;
            while (left < right){
                char temp = s[left];
                s[left] = s[right];
                s[right] = temp;
                left++;
                right--;
            }
            System.out.println(s);
        }
    }
}